Proof of P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Proof of P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

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Proof that (P(A) △ P(B)) ∩ P(A △ B) = ∅ and A = B are Equivalent
Proof that (P(A) △ P(B)) ∩ P(A △ B) = ∅ and A = B are Equivalent
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